| 1. | That can be determined by evaluating the quadratic term of a divided difference formula.
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| 2. | At high frequencies the quadratic term becomes important.
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| 3. | Quadratic terms in and arise, which give masses to the W and Z bosons:
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| 4. | Subtracting one equation from another eliminates these quadratic terms, leaving only the linear ones.
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| 5. | Since each vibrational modes contributes to two quadratic terms in the Hamiltonian, you get:
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| 6. | Partial pivoting adds only a quadratic term; this is not the case for full pivoting.
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| 7. | The spatial symmetry of the problem is responsible for canceling the quadratic term of the expansion.
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| 8. | In fact, this is the origin of the quadratic term in the field strength tensor.
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| 9. | The same behavior can be obtained from the functional integrals, omitting the quadratic terms in the action.
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| 10. | Lord Rayleigh investigated this first and quantified the magnetization M as a linear and quadratic term in the field:
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